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Brainiac [The Archive] - (y^4x^2 + 2xy – y)/(x – 1) = 12
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Треки
ε0 = 8.854187817 × 10^(-12) F.m-1
Brainiac [The Archive]
Epsilon Naught
1:27
N⋅m^2⋅C−2
Brainiac [The Archive]
Epsilon Naught
1:15
1 = 0 ∪ {0} = {} ∪ {0} = {0}
Brainiac [The Archive]
Epsilon Naught
1:27
9*10^9
Brainiac [The Archive]
Epsilon Naught
1:10
e^2⋅GeV^-1⋅fm^-1
Brainiac [The Archive]
Epsilon Naught
1:04
d x ( x n ) = n x n − 1
Brainiac [The Archive]
Epsilon Naught
1:16
f′(x)=nxn−1
Brainiac [The Archive]
Epsilon Naught
1:19
f(x)=xn f ( x ) = x n
Brainiac [The Archive]
Epsilon Naught
1:31
3x^2+12x−23=0
Brainiac [The Archive]
Epsilon Naught
1:29
(y^4x^2 + 2xy – y)/(x – 1) = 12
Brainiac [The Archive]
Epsilon Naught
0:54
csc^2 x dx = − cot x + C
Brainiac [The Archive]
Epsilon Naught
0:52
tan x dx = − ln | cos x| + C
Brainiac [The Archive]
Epsilon Naught
1:41
d/dx cot x = − csc 2 x
Brainiac [The Archive]
Epsilon Naught
1:08
d/dx ln |x| = 1/x
Brainiac [The Archive]
Epsilon Naught
1:11
dy/dx = x^-2 .
Brainiac [The Archive]
Epsilon Naught
1:20
y = f(x) = x^p
Brainiac [The Archive]
Epsilon Naught
1:09
y = x^11 e^6x
Brainiac [The Archive]
Epsilon Naught
1:54
log5(0.2) = –1
Brainiac [The Archive]
Epsilon Naught
1:29
lim 1/x = 0.
Brainiac [The Archive]
Epsilon Naught
1:25
d/dx (e^ax) = a e^ax
Brainiac [The Archive]
Epsilon Naught
1:14
p x^p-1
Brainiac [The Archive]
Epsilon Naught
1:07
d/dx [logb(x)] = 1/x 1/ln(b)
Brainiac [The Archive]
Epsilon Naught
1:34
y = f(x) = C
Brainiac [The Archive]
Epsilon Naught
1:29
y = x^3/2 - 7x^4 +10e^-3x - 5
Brainiac [The Archive]
Epsilon Naught
1:25
f′(x)=nxn−1ORddx(xn)=nxn−1
Brainiac [The Archive]
Epsilon Naught
1:04
U=Q^2/2C
Brainiac [The Archive]
Epsilon Naught
1:15
mv dt-dv
Brainiac [The Archive]
Epsilon Naught
1:04